Bow down all before me...
Dec. 15th, 2005 11:20 pm![[personal profile]](https://www.dreamwidth.org/img/silk/identity/user.png){kind=small}
compilerbitch... for, according to the American Mathematical Society, I have an Erdös number of 5.
The chain goes Me → Alan Mycroft → Richard A. O'Keefe → Leon Sterling → Nicholas C. Wormald → Paul Erdös.
Woohoo!
(for those of you who don't know what on earth I'm talking about, look here)
Edit: I have been playing a bit with the AMS web site. It seems I have an Alan Turing number of 7, a Carl Friedrich Gauss number of 9 and a Catherine Greenhill number of 5 (not that many of you know here, but![[livejournal.com profile]](https://www.dreamwidth.org/img/external/lj-userinfo.gif)
galliana knows her well).
The chain goes Me → Alan Mycroft → Richard A. O'Keefe → Leon Sterling → Nicholas C. Wormald → Paul Erdös.
Woohoo!
(for those of you who don't know what on earth I'm talking about, look here)
Edit: I have been playing a bit with the AMS web site. It seems I have an Alan Turing number of 7, a Carl Friedrich Gauss number of 9 and a Catherine Greenhill number of 5 (not that many of you know here, but
galliana knows her well).
(no subject)
Date: 2005-12-16 09:46 am (UTC)Hmm. Last time I looked at that page, ISTR it said there was one single mathematician with the highest Erdős number of 14. I remember thinking at the time that he must be really proud of that, but that it's much harder to maintain than a low number: he was probably scared that someone on his minimal chain would collaborate with someone lower down and reduce his number. (And the chance of him collaborating with anyone was probably tiny.) But today the page says the highest is 13, which presumably means this has now happened.