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If I entangle two particles A and B in such a way that they are in the same quantum state, then entangle them such that they are in different quantum states, what happens?
1. The universe ends with the biggest core dump in the history of the multiverse
2. Both particles cease to exist in some kind of impressive explosively thrown exception
3. Both particles end up entangled to be in the same state
4. Both particles end up entangled to be in different states
5. Both particles end up entangled, but are randomly entangled as in 4. or 5. above
6. Entanglement is broken, with both particles left in random states
7. Doing what I said is impossible for some clever but not immediately obvious reason
8. I am asking a stupid question (though I'd argue that knowing exactly why it is stupid would be valuable)
(note that 5 and 6 are not equivalent if either particle ends up further entangled)
The same problem, from a quantum computing point of view, could be restated a bit more simply. Given N classical bits, the number of possible combinations of values is 2N. With N qubits in a mutually entagled state, the number of possible combinations is strictly less than 2N, such that if an observation (and collapse to a classical, non-superposed state) is forced, the resulting classical value is constrained by the original entangled state. My question is, what happens if the entangled state allows exactly zero possible classical values?
1. The universe ends with the biggest core dump in the history of the multiverse
2. Both particles cease to exist in some kind of impressive explosively thrown exception
3. Both particles end up entangled to be in the same state
4. Both particles end up entangled to be in different states
5. Both particles end up entangled, but are randomly entangled as in 4. or 5. above
6. Entanglement is broken, with both particles left in random states
7. Doing what I said is impossible for some clever but not immediately obvious reason
8. I am asking a stupid question (though I'd argue that knowing exactly why it is stupid would be valuable)
(note that 5 and 6 are not equivalent if either particle ends up further entangled)
The same problem, from a quantum computing point of view, could be restated a bit more simply. Given N classical bits, the number of possible combinations of values is 2N. With N qubits in a mutually entagled state, the number of possible combinations is strictly less than 2N, such that if an observation (and collapse to a classical, non-superposed state) is forced, the resulting classical value is constrained by the original entangled state. My question is, what happens if the entangled state allows exactly zero possible classical values?